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xusun0623
exam_code_for_408
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2019_code_cross.cpp
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master
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2019_code_cross.cpp
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#
include
<
stdio.h
>
#
include
<
stdlib.h
>
typedef
struct
node
{
int
data;
struct
node
* next;
}
NODE
;
//
通过数组创建链表
void
create
(node* n,
int
length,
int
pos,
int
data[]) {
if
(pos < length) {
n->
data
= data[pos];
//
赋给struct中的data
node* next = (node*)
malloc
(
sizeof
(node));
//
动态分配下一个节点地址
n->
next
= next;
//
对下一个节点采用递归构建
create
(n->
next
, length, pos +
1
, data);
//
递归,pos位置+1
}
else
{
n->
data
= -
1
;
//
最后一个节点使用-1作为标识
}
}
void
cross_sort
(node* n,
int
length) {
//
对后半部分就地逆置
node* mid = n;
node* start = n;
int
i;
for
(i =
0
;i < length /
2
;i++)mid = mid->
next
;
//
找到中间节点
//
从中间开始逆置链表
node* s, * t;
s = mid->
next
;
mid->
next
=
NULL
;
while
(s->
data
!= -
1
) {
//
将s节点摘下来
t = s;
s = s->
next
;
//
将摘下来的节点头插到mid节点之后
t->
next
= mid->
next
;
mid->
next
= t;
}
node* tmp = mid;
mid = mid->
next
;
//
后移
tmp->
next
=
NULL
;
i++;
while
(i++ < length && mid !=
NULL
) {
node* p, * q;
//
使用p、q暂存start和mid节点
p = start->
next
;
q = mid->
next
;
//
将mid指针所指节点单独摘下来,注意:要将尾巴(next)甩掉,不然结果不对
mid->
next
=
NULL
;
//
插到start节点后面
start->
next
= mid;
mid->
next
= p;
//
同时移动start和end指针
start = p;
mid = q;
}
mid =
NULL
;
}
int
main
() {
node* a = (node*)
malloc
(
sizeof
(node));
int
d[] = {
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
};
create
(a,
8
,
0
, d);
cross_sort
(a,
8
);
return
0
;
}
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